An aircraft travelling at 600km/h accelerates steadily at 10 km/h . Taking the speed of sound as 1100 km/h at the aircraft's altitude , how long will it take to reach sound barrier?
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Solution
The aircraft has to cross sound barrier ,i.e. v=1100 km/h =1100 x 5/18= 2750/9 m/s
u=600 km/h = 600 x 5/18 = 1500/9 m/s
the acceleration of the aircraft is 10 km/h per second a= 10 km/h/s = 10 x 5/18 m/s/s = 25/9 m/s^2
using first equation of motion v = u+at 2750/9= 1500/9 + 25t/9 2750 = 1500 + 25 t 2750 - 1500 / 25 = 1250/25 = 50s hence the aircraft will cross the sound barrier in 50 secs
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