An airplane with wingspan $50 m$ is flying horizontally with a speed of $360 k m h r^{- 1}$ over a place where the vertical component of the earth's magnetic field is $2 \times 10^{- 2}$ . The potential difference between the tips of the wings would be

100 V

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1.0 V

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0.2 V

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0.01 V

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Solution

The correct option is A $100 V$
emf between the wing tips $= B l v$

$= 0.02 \times 50 \times 360 \times \frac{1000}{3600}$

$= 100 V$

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An airplane with wingspan 50m is flying horizontally with a speed of 360kmhr−1 over a place where the vertical component of the earth's magnetic field is 2×10−2. The potential difference between the tips of the wings would be

The correct option is A 100Vemf between the wing tips =Blv=0.02×50×360×10003600=100V

An airplane with wingspan $50 m$ is flying horizontally with a speed of $360 k m h r^{- 1}$ over a place where the vertical component of the earth's magnetic field is $2 \times 10^{- 2}$ . The potential difference between the tips of the wings would be

The correct option is A $100 V$
emf between the wing tips $= B l v$

$= 0.02 \times 50 \times 360 \times \frac{1000}{3600}$

$= 100 V$