An alcohol contains 60% carbon and 13.3% hydrogen and shows a positive iodoform test. The alcohol is:

2-propanol

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1-propanol

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2-butanol

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1-butanol

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Solution

The correct option is A 2-propanol
$C : H : O$ = $\frac{60}{12} : \frac{13.3}{1} : \frac{26.7}{16}$

$C : H : O$ = 3 : 8 : 1

The formulae of the compound is $C_{3} H_{8} O$ .

Since the alcohol gives iodoform test, it is 2- propanol.

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An alcohol contains 60% carbon and 13.3% hydrogen and shows a positive iodoform test. The alcohol is:

The correct option is A 2-propanolC:H:O = 6012:13.31:26.716 C:H:O = 3 : 8 : 1 The formulae of the compound is C3H8O. Since the alcohol gives iodoform test, it is 2- propanol.

The correct option is A 2-propanol
$C : H : O$ = $\frac{60}{12} : \frac{13.3}{1} : \frac{26.7}{16}$

$C : H : O$ = 3 : 8 : 1

The formulae of the compound is $C_{3} H_{8} O$ .

Since the alcohol gives iodoform test, it is 2- propanol.