An algebraic expression for one-fourth of $m$ added to the quotient of $n \div 3$ is:

$\frac{1}{4} m + \frac{3}{n}$

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$\frac{1}{4} m + \frac{n}{3}$

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$\frac{1}{4} m + 3 n$

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$\frac{1}{4} m - 3 n$

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Solution

The correct option is B
$\frac{1}{4} m + \frac{n}{3}$

Here one-fourth of m $\frac{1}{4} m$
and quotient of $n \div 3 = \frac{n}{3}$
Then the sum is $\frac{1}{4} m + \frac{n}{3}$

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