An alkali metal hybride(NaH) reacts with diborane in ‘A’ to give a tetrahedral compound ‘B’ which is extensively used as reducing agent in organic synthesis. The compounds ‘A’ and ‘B’ respectively are

$C_{2} H_{6} a n d C_{2} H_{5} N a$

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$C H_{3} C O C H_{3} a n d B_{3} N_{3} H_{6}$

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$C_{6} H_{6} a n d N a B H_{4}$

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$(C_{2} H_{5})_{2} O a n d N a B H_{4}$

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Solution

The correct option is D
$(C_{2} H_{5})_{2} O a n d N a B H_{4}$

$2 N a H + B_{2} H_{6} (C_{2} H_{5})_{2} O - ----- \to 2 N a B H_{4}$

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An alkali metal hybride(NaH) reacts with diborane in ‘A’ to give a tetrahedral compound ‘B’ which is extensively used as reducing agent in organic synthesis. The compounds ‘A’ and ‘B’ respectively are

The correct option is D (C2H5)2O and NaBH4 2NaH+B2H6(C2H5)2O−−−−−−→2NaBH4

The correct option is D
$(C_{2} H_{5})_{2} O a n d N a B H_{4}$

$2 N a H + B_{2} H_{6} (C_{2} H_{5})_{2} O - ----- \to 2 N a B H_{4}$