An alkali metal hydride (NaH) reacts with diborne in 'A' to give a tetrahedral compound 'B' which is extremely used as reducing agent in organic synthesis. The compounds 'A' and 'B' respectively are :
A
C2H6 and C2H5Na
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B
CH3COCH3 and B3N3H6
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C
C6H6 and NaBH4
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D
(C2H5)2O and NaBH4
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Solution
The correct option is D(C2H5)2O and NaBH4 An alkali metal hydride (NaH) reacts with diborne in 'A' ((C2H5)2O) to give a tetrahedral compound 'B' (NaBH4) which is extremely used as reducing agent in organic synthesis. The compounds 'A' and 'B' respectively are (C2H5)2O and NaBH4. 2NaH+B2H6(C2H5)2O−−−−−−→2NaBH4