An alkaloid contains 17.28% of nitrogen and its molecular mass is 162. The number of nitrogen atoms present in one molecule of alkaloid is:

Five

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Four

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Three

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Two

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Solution

The correct option is D Two
$W = \frac{17.2 \times 162}{100} = 28$
Number of atoms is equals to weight/moleculrweight
So 28/14 is equals to 2
So 2 atoms are present in the given alkaloid.

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An alkaloid contains 17.28% of nitrogen and its molecular mass is 162. The number of nitrogen atoms present in one molecule of alkaloid is:

The correct option is D TwoW=17.2×162100=28Number of atoms is equals to weight/moleculrweightSo 28/14 is equals to 2So 2 atoms are present in the given alkaloid.

The correct option is D Two
$W = \frac{17.2 \times 162}{100} = 28$
Number of atoms is equals to weight/moleculrweight
So 28/14 is equals to 2
So 2 atoms are present in the given alkaloid.