An alkane C6H14(X) can be obtained by the reduction of five different alkyl halides C6H13Cl (only structural isomers) with Zn−dil.HCl. The IUPAC name of X satisfying above condition is
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Solution
2-methyl pentane has five types of hydrogen, therefore, it can be obtained by reduction of five different halides as:
All of the above chloroalkanes, reduction with Zn−dil.HCl would give the same 2-methyl pentane.