An alkane with molecular formula C 6 H 14 gives two monochloro alkanes on chlorination- What is the structure of alkane-A- CH 3- CH 2- CH 2- CH 2- CH 2- CH 3B- - CH 3 CH 3- CH 3- CH CH - CH 3 -C- CH 3CH 3- CH - CH 2- CH 2- CH 3D- CH 3- CH 3 CH 3 C 3- CH 2- CH 3

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Saturated Hydrocarbons

An alkane wit...

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An alkane with molecular formula $C_{6} H_{14}$ gives two monochloro alkanes on chlorination. What is the structure of alkane?

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{CH}_{3} - {CH}_{2} - CH = {CH}_{3}

S_{N} 2

c o n c . H C l :

(a) C H_{3} - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{2} - C l

(b) C H_{3} - C H_{3} | C | C H_{3} - C H_{2} O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{1} | C | C H_{3} - C H_{2} - C H_{3}

(c) C H_{3} - O H | C | C H_{3} - C H_{3} A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C l | C | C H_{3} - C H_{3}

(d) C H_{2} = C H - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{2} = C H - C H_{2} - C l

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

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