Distinguishing Test of Terminal and Non Terminal Alkynes
An alkene 'A'...
Question
An alkene 'A' on ozonolysis yield only ethanal. The chain isomer of 'A' on ozonolysis yields-
A
CH3−CO−CH3
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B
CH3−CHO
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C
HCHO
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D
CH3−CH2−CHO
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Solution
The correct option is CHCHO Ozonolysis of alkenes involves the addition of an ozone molecule to analkene, to form an ozonide. Formed ozonide gets cleavedby Zn−H2O to smaller oxidised molecules.
To find the compound involved in ozonolysis just eliminate the oxidised part (i.e. oxygen) of products and combine them with a double bond.
Alkene 'A' on ozonolysis gives only ethanal so it is a symmetrical alkene. Thus, eliminating the oxidised part of ethanal and combing them with a double bond gives 2-Butene.
This is shown clearly in the below diagram,
The only possible chain isomer of 'A' is
2-Methylprop-1-ene
The ozonolysis product of 2-Methylprop-1-ene are acetone and formaldehyde