An alkene on vigorous oxidation with $K M n O_{4}$ gives only acetic acid. The alkene is :

C H_{3} C H_{2} C H = C H_{2}

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C H_{3} C H = C H C H_{3}

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(C H_{3})_{2} C = C H_{2}

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C H_{3} C H = C H_{2}

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Solution

The correct option is A $C H_{3} C H = C H C H_{3}$
Since, the alkene on oxidation gives only aeetic acid, therefore, the alkene must be symmetrical, containing two C-atoms on either side of the double bond i.e., 2-butene.
$C H_{3} C H = C H C H_{3} K M n O_{4} - ---- \to 2 C H_{3} C O O H$

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