An alkyl bromide $(X)$ reacts with sodium in ether to form 4, 5-diethyl octane, the compound $X$ is :

C H_{3} {(C H_{2})}_{3} B r

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C H_{3} {(C H_{2})}_{5} B r

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C H_{3} {(C H_{2})}_{3} C H (B r) C H_{3}

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C H_{3} - {(C H_{2})}_{2} - C H (B r) - C H_{2} - C H_{3}

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Solution

The correct option is D $C H_{3} - {(C H_{2})}_{2} - C H (B r) - C H_{2} - C H_{3}$
$2 C H_{3} (C H_{2})_{2} C H (B r) C H_{2} C H_{3} N a, e t h e r - ---- \to 4, 5 - d i e t h y l o c t a n e$

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