Question

An alkyl halide reacts with alcoholic ammonia in a sealed tube, and the product formed will be:

• A. Primary amine
• B. Secondary amine
• C. Tertiary amine
• D. All of these

Answer 1

The correct option is D

All of these

Explanation of correct option

(D)All of these

The reaction of alkyl halide reacts with alcoholic ammonia

• An alkyl halide reacts with alcoholic ammonia in a sealed tube, formation of primary amine takes place.
• The reaction is as follows:-
• $\mathrm{R}-\mathrm{X}+{\mathrm{NH}}_3\to \mathrm{R}-{\mathrm{NH}}_2+\mathrm{HX}$
• The reaction doesn't stop there and primary amine further gives secondary amine. Secondary gives tertiary.
• $$\begin{gathered} \mathrm{R}-{\mathrm{NH}}_2+\mathrm{HX}\to {\mathrm{R}}_2-\mathrm{NH}+\mathrm{HX} \\ {\mathrm{R}}_2-\mathrm{NH}+\mathrm{HX}\to {\mathrm{R}}_3-\mathrm{N}+\mathrm{HX} \end{gathered}$$

Hence, option (D) is correct. An alkyl halide reacts with alcoholic ammonia in a sealed tube, and the product formed will be a primary, secondary, and tertiary amine.