An alloy consists of zinc and iron in the ratio $3 : 5 .$ How much iron is there in $40 k g$ of the alloy $?$

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Solution

The given ratio is $3 : 5 .$
Let ,the weight of zinc is $3 x$ , and iron is $5 x$
The weight of the alloy is $40 k g$
Now, the weight of the alloy $=$ the weight of zinc $+$ the weight of iron.
$40 = 3 x + 5 x$
$\Rightarrow x = \frac{40}{8} = 5$
The weight of iron $= 5 x = 5 \times 5$
$= 25 k g$
Hence, the weight of iron is $25 k g$ .

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