An alpha nucleus of energy 12mv2eV bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to
A
1Ze
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B
v2
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C
1m
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D
1v2
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Solution
The correct options are C1m D1v2 The point when the bombarded nucleus is nearest to the target, the whole K.E is changed into P.E. ∴mv22=KZe2d d=2KZe2v2×1m