MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Kirchoff's Voltage Law

an Alpha part...

Question

an Alpha particle completes 40,000 revolutions in a cyclotron before exiting from . if potential difference between the dees is 5000 volt then energy gained by particle is 1. 8MeV 2. 800MeV

Open in App

Solution

Suggest Corrections

thumbs-up

4

Similar questions

Q. Estimate the kinetic energy gained by a proton in one revolution if the potential gap between the Dees is

80 kV

in a cyclotron.

Q. A proton is accelerating in a cyclotron where the applied magnetic field is

2 T

. If the potential gap is effectively

100 kV

, then how many revolutions the proton has to make between the dees to acquire a kinetic energy of

20 MeV

Q. A cyclotron with two cylindrical dees

(

)

, as shown in the figure, is used to accelerate proton of mass

m = 1.6 \times 10^{- 27} k g

1.6 \times 10^{- 19} C

by applying a potential difference of

100 k V

between the dees. A magnetic field of

1 T

is applied normal to the plane of dees of maximum radius of

50 c m

. The number of revolutions made by the protons just before coming out of the cyclotron will be about whenever a protons leaves one of the dees , other will kept at proper polarity, is

Q. An alpha particle is accelerated through a potential difference of

10^{6}

volt. Its kinetic energy will be :

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Kirchoff's Voltage Law

PHYSICS

Watch in App

explore_more_icon

Explore more

Kirchoff's Voltage Law

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon