Charge on the alpha particle = 2e
Potential difference = 106V Step 2, Finding the kinetic energy
We know,
Kinetic energy = Work done = q×V
Putting all the values
Kinetic energy = 2e×106V=2×106eV
Or, Kinetic energy = 2 MeV
At what temperature the linear kinetic energy of a gas molecule will be equal to that of an electron accelerated through a potential difference of 10 volt?