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Question

An alpha particle is accelerated through a potential difference of 106 volt. Its kinetic energy will be

A
1 MeV
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B
2 MeV
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C
4 MeV
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D
8 MeV
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Solution

The correct option is B 2 MeV
Step 1, Given data

Charge on the alpha particle = 2e

Potential difference = 106V
Step 2, Finding the kinetic energy

We know,

Kinetic energy = Work done = q×V

Putting all the values

Kinetic energy = 2e×106V=2×106eV

Or, Kinetic energy = 2 MeV


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