An alpha particle is accelerated through a potential difference of $10^{6}$ volt. Its kinetic energy will be

1 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 MeV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 MeV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 2 MeV
Step 1, Given data
Charge on the alpha particle = 2e
Potential difference = $10^{6} V$
Step 2, Finding the kinetic energy
We know,
Kinetic energy = Work done = $q \times V$
Putting all the values
Kinetic energy = $2 e \times 10^{6} V = 2 \times 10^{6} e V$
Or, Kinetic energy = 2 MeV

Suggest Corrections

Similar questions

Q. An alpha particle is accelerated through a potential difference of

10^{6} volt

. Its kinetic energy will be

Q. An

α

-particle has initial kinetic energy of 25 eV and it is accelerated through the potential difference of 150 volt. If a proton has initial kinetic energy of 25 eV and it is accelerated through the potential difference of 25 volt then find the approximate ratio of the final wavelengths associated with the proton and the

α

particle.

Q. The energy acquired by a charged particle of

4 μ C

when it is accelerated through a potential difference of 8 Volt will be :

At what temperature the linear kinetic energy of a gas molecule will be equal to that of an electron accelerated through a potential difference of 10 volt?

Q. An

α -

particle passes through a potential difference of

2 \times 10^{6}

volt and then it becomes incident on a silver foil. The charge number of silver is

47

, the kinetic energy of

α -

particles at a distance

5 \times 10^{- 14}

m from the nucleus will be (in joules).

Join BYJU'S Learning Program

An alpha particle is accelerated through a potential difference of 106 volt. Its kinetic energy will be

The correct option is B 2 MeVStep 1, Given dataCharge on the alpha particle = 2ePotential difference = 106V Step 2, Finding the kinetic energyWe know,Kinetic energy = Work done = q×V Putting all the valuesKinetic energy = 2e×106V=2×106eV Or, Kinetic energy = 2 MeV

An alpha particle is accelerated through a potential difference of $10^{6}$ volt. Its kinetic energy will be