Question

An $\alpha$-particle is bombarded on ${}^{14}\text{N}$. As a result, a ${}^{17}\text{O}$ nucleus is formed and a particle is emitted. This particle is a

• A. neutron
• B. proton
• C. electron
• D. positron

Answer 1

Answer: (B)

proton

The equation of the reaction will be ${}_7{N}^{14}{+}_{2}H{e}^4(\alpha -particle){\to }_8{O}^{17}{+}_p{X}^a\left(unknown\right)$

The proton number and mass number should be same from both side.

So, $7+2=8+p$ or $p=1$ and $14+4=17+a$ or $a=1$

Thus, the unknown particle is ${}_1{H}^1$ i.e proton.