An alpha particle is projected vertically upward with a speed of $3.0 \times 10^{4}$ km $s^{- 1}$ in a region where a magnetic field of magnitude 1.0 T exists in the direction south to north. Find the magnetic force that acts on the $α -$ particle.

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Solution

$q = 2 \times 1.6 \times 10^{- 19} C,$

$v = 3 \times 10^{4}$ km/s $= 3 \times 10^{7}$ m/s

B = 1 T, F = qBv

$= 2 \times 1.6 \times 10^{- 19} \times 3 \times 10^{7} \times 1$

$= 9.6 \times 10^{- 12}$ m/s.

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Q. An alpha particle is projected vertically upward with a speed of

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Question 3
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An alpha particle is projected vertically upward with a speed of 3.0×104 km s−1 in a region where a magnetic field of magnitude 1.0 T exists in the direction south to north. Find the magnetic force that acts on the α− particle.

q=2×1.6×10−19C, v=3×104 km/s =3×107 m/s B = 1 T, F = qBv =2×1.6×10−19×3×107×1 =9.6×10−12 m/s.

An alpha particle is projected vertically upward with a speed of $3.0 \times 10^{4}$ km $s^{- 1}$ in a region where a magnetic field of magnitude 1.0 T exists in the direction south to north. Find the magnetic force that acts on the $α -$ particle.

$q = 2 \times 1.6 \times 10^{- 19} C,$

$v = 3 \times 10^{4}$ km/s $= 3 \times 10^{7}$ m/s

B = 1 T, F = qBv

$= 2 \times 1.6 \times 10^{- 19} \times 3 \times 10^{7} \times 1$

$= 9.6 \times 10^{- 12}$ m/s.