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Question

An alpha-particle of mass m suffers 1-dimensional elastic collision with a nucleus at rest of unknown mass. It is scattered directly backwards losing, 64% of its initial kinetic energy. The mass of the nucleus is:-

A
4m
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B
3.5m
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C
2m
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D
1.5m
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Solution

The correct option is A 4m
mv0=mv2mv1
12mV21=0.36×12mV20
v1=0.6v0
12MV22=0.64×12mV20
V2=mM×0.8V0
mV0=mM×0.8V0m×0.6V0
1.6m=0.8mM
4m2=mM

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