An alternating current in circuit is given by I=20sin(100πt+0.005π)A. The r.m.s value and the frequency of current respectively are:
A
10A and 100Hz
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B
10A and 50Hz
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C
10√2A and 50Hz
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D
10√2A and 100Hz
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Solution
The correct option is B10√2A and 50Hz Given I=20sin(100πt+0.005π)A The root mean square value of alternating current =Irms=I0√2=20√2=10√2A Also, ω=100π ⇒2πf=100π or f=50Hz