An alternating current is given by the equation, $i = 3 \sqrt{2} sin (100 π t + π / 4)$ and an alternating voltage is given by the equation, $E = 220 \sqrt{2} sin (100 π t + π / 2)$ . Calculate the phase difference between them.

π / 4

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π / 3

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π / 2

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π / 6

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Solution

The correct option is A $π / 4$
Given:

Current, $i = 3 \sqrt{2} sin (100 π t + π / 4) \Rightarrow ϕ_{1} = 100 π t + π / 4$
Voltage, $E = 220 \sqrt{2} sin (100 π t + π / 2) \Rightarrow ϕ_{2} = 100 π t + π / 2$

Therefore, phase difference,

$Δ ϕ = ϕ_{2} - ϕ_{1} = 100 π t + π / 2 - (100 π t + π / 4) = π / 4$

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