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Question

An alternating e.m.f. of angular frequency ω is applied across an inductance. The instantaneous power developed in the circuit has an angular frequency

A
ω4
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B
ω2
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C
ω
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D
2ω
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Solution

The correct option is D 2ω
The instantaneous values of emf and current in inductive circuit are given by E=E0sinωt and i=i0sin(ωtπ2) respectively.
So, Pinstantaneous=EI=E0sinωt×i0sin(ωtπ2)=E0i0sinωt(sinωtcosπ2cosωtsinπ2)=E0i0sinωtcosωt=12E0i0sin2ωt (sin2sinωt=2sinωtcosωt)
Hence, angular frequency of instantaneous power is 2ω

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