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Question

An alternating emf of angular frequency ω is applied across an inductance. The instantaneous power developed in the circuit has an angular frequency :

A
ω4
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B
ω2
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C
ω
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D
2ω
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Solution

The correct option is A 2ω
The instantaneous values of emf and current in inductive circuit are given by
[E=E0sinωt] and [i=i0sin(ωtπ2)] respectively.

So, [Pinst=Ei=E0sinωt×i0sin(ωtπ2)]

[=E0i0sinωt(sinωtcosπ2cosωtsinπ2)]

[=E0i0sinωt cosωt]

[=12E0i0sin2ωt]

[(sin2ωt=2sinωt cosωt)]

Hence, angular frequency of instantaneous power is [2ω].

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