Question

An alternating voltage$E=200sin\left(300t\right)$ volt is applied across a series combination of $R=10\Omega$ and inductance of $800mH$. Calculate the impedance of the circuit.

Answer 1

Given : $L=800mH$ $R=10\Omega$
Alternating source voltage $E=200\sin \left(300t\right)$
Comparing with $E=E_{o}sinwt$
we get $w=300$
Inductive reactance $X_L=wL=300\times 800\times {10}^{-3}=240\Omega$
Impedance of the circuit $Z=\sqrt{R^2+X_L^2}$
$⟹Z=\sqrt{{10}^2+{240}^2}=240.21\Omega$