Question

An alternating voltage $E=50\sqrt{2}\sin \left(100t\right)V$ is connected to a $1\mu F$ capacitor through an ac ammeter. What will be the reading of the ammeter?

• A. $10mA$
• B. $5mA$
• C. $5\sqrt{2}mA$
• D. $10\sqrt{2}mA$

Answer 1

The correct option is B $5mA$

$X_C=\frac{1}{C\omega }=10000\Omega$
ammeater reading = $I_{rms}=\frac{V_{rms}}{\left|j{X}_C\right|}=\frac{50}{10000}=5mA$