Question

An alternating voltage $E=50\sqrt{2}\sin \left(100t\right)V$ is connected to a 1 μF capacitor through an ac ammeter. The reading of ammeter will be .

• A. 10 mA
• B. 5 mA
• C. 5$\sqrt{2}$ mA
• D. 10$\sqrt{2}$ mA

Answer 1

The correct option is B 5 mA

$X_c=\frac{1}{\omega C}=\frac{1}{100\times {10}^{-6}}={10}^4\Omega So,I_{rms}=\frac{E_{rms}}{Z}=\frac{50\sqrt{2}}{\sqrt{2}{10}^4}=5mA.$