Question

An alternating voltage $E\text{(in volt)}=300\sqrt{2}\sin \left(100t\right)$ is connected to a $2\mu \text{F}$ capacitor through an AC ammeter. The reading of the ammeter would be

• A. $30\text{mA}$
• B. $60\text{mA}$
• C. $20\text{mA}$
• D. $40\text{mA}$

Answer 1

The correct option is B $60\text{mA}$

The capacitive reactance is given by
$X_C=\frac{1}{\omega C}=\frac{1}{100\times 2\times {10}^{-6}}=5\times {10}^3\Omega$

$\because I=\frac{V}{X_c}$
$\Rightarrow I=\frac{300}{5\times {10}^3}=60\times {10}^{-3}=60\text{mA}$