Question

An alternating voltage is connected in series with a resistance R and an inductance L If the potential drop across the resistance is 200 V and across the inductance is 150 V, then the applied voltage is

• A. 350 V
• B. 250 V
• C. 500 V
• D. 300 V

Answer 1

The correct option is B 250 V

The applied voltage is given by $V=\sqrt{V_R^2+V_L^2}$
$V=\sqrt{(200{)}^2+(150{)}^2}=250volt$