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Standard XII

Physics

Self Induction

An alternatin...

Question

An alternating voltage is connected in series with a resistance R and an inductance L. If the potential drop across the resistance is 200 volt and across the inductance is 150 volt, the applied voltage is

350 volt

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250 volt

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500 volt

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300 volt

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Solution

The correct option is B 250 volt
$T o t a l P D = \sqrt{P D_{I n d u c t a n c e}^{2} + P D_{r e s i s t a n c e}^{2}}$
$P D = \sqrt{150^{2} + 200^{2}}$
$= 250 V$

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An alternating voltage is connected in series with a resistance R and an inductance L. If the potential drop across the resistance is 200 volt and across the inductance is 150 volt, the applied voltage is

The correct option is B 250 voltTotalPD=√PD2Inductance+PD2resistancePD=√1502+2002=250V

The correct option is B 250 volt
$T o t a l P D = \sqrt{P D_{I n d u c t a n c e}^{2} + P D_{r e s i s t a n c e}^{2}}$
$P D = \sqrt{150^{2} + 200^{2}}$
$= 250 V$