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Standard XII

Physics

Capacitor in an AC Circuit

An alternatin...

Question

An alternating voltage of $220 V, 50 H z$ frequency is applied across a capacitor of capacitance $2 μ F$ . The impedence of the circuit is:

\frac{π}{5000}

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\frac{1000}{π}

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500 π

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\frac{5000}{π}

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Solution

The correct option is D $\frac{5000}{π}$
Impedence of a capacitor is $X_{C} = 1 / ω C$
$X_{C} = \frac{1}{2 π f C} = \frac{1}{2 π \times 50 \times 2 \times 10^{- 6}} = \frac{5000}{π}$

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An alternating voltage of 220V,50Hz frequency is applied across a capacitor of capacitance 2μF. The impedence of the circuit is:

The correct option is D 5000πImpedence of a capacitor is XC=1/ωCXC=12πfC=12π×50×2×10−6=5000π

An alternating voltage of $220 V, 50 H z$ frequency is applied across a capacitor of capacitance $2 μ F$ . The impedence of the circuit is:

The correct option is D $\frac{5000}{π}$
Impedence of a capacitor is $X_{C} = 1 / ω C$
$X_{C} = \frac{1}{2 π f C} = \frac{1}{2 π \times 50 \times 2 \times 10^{- 6}} = \frac{5000}{π}$