Question

An alternating voltage V = 200 sin 100t, where V is in volt and t seconds, is connected to a series combination of 1$\mu$ farad capacitor and 10K $\Omega$ resistor through an AC ammeter. The reading of the ammeter will be

• A. $\sqrt{2}mA$
• B. $10\sqrt{2}mA$
• C. $2mA$
• D. $10mA$

Answer 1

The correct option is D $10mA$

$I_{rms}=\frac{V_{rms}}{\sqrt{R^2+{\left[\frac{1}{w_C}\right]}^2}}$
$=\frac{200}{\sqrt{2}\sqrt{(10\times {10}^3{)}^2+{\left[\frac{1}{100\times {10}^{-6}}\right]}^2}}$
$=\frac{200}{\sqrt{2}\times {10}^4\sqrt{2}}={10}^2\times {10}^{-4}$
$=10\times {10}^{-3}A$
= 10 mA