Question

An alternating voltage $V=200\sqrt{2}\sin 100t$, Where $V$ is in volt and $t$ is in seconds, is connected to a series combination of 1$\mu \text{F}$ capacitor and $10\text{k}\Omega$ resistor through an AC ammeter. The reading of the ammeter will be_____

• A. $\sqrt{2}\text{mA}$
• B. $10\sqrt{2}\text{mA}$
• C. $2\text{mA}$
• D. 20mA

Answer 1

The correct option is B $10\sqrt{2}\text{mA}$

$i=\frac{V_{rms}}{\sqrt{R^2+{(\frac{1}{\omega C}-\omega L)}^2}}$
$\Rightarrow i=\frac{200\sqrt{2}\frac{1}{\sqrt{2}}}{\sqrt{{10000}^2+{(\frac{1}{100\times {10}^{-6}}-100\times 0)}^2}}=\frac{200}{\sqrt{{2\times 10000}^2}}$
$=10\sqrt{2}mA$