Question

An aluminium block of 2m mass and an iron block of m mass,each absorbs the same amount of heat, and both blocks remain solid. If the specific heat of aluminium is twice the specific heat of iron, then find out the correct statement?

• A. The increase in temperature of the aluminum block is twice the increase in temperature of the iron block
• B. The increase in temperature of the aluminum block is four times the increase in temperature of the iron block
• C. The increase in temperature of the aluminum block is the same as increase in temperature of the iron block
• D. The increase in temperature of the iron block is twice the increase in temperature of the aluminum block
• E. The increase in temperature of the iron block is four times the increase in temperature of the aluminum block

Answer 1

The correct option is E The increase in temperature of the iron block is four times the increase in temperature of the aluminum block

The heat required to rise the temperature of body of mass $m$ of specific heat $s$ by $\Delta T=H=ms\Delta T$

Thus for same amount of heat, the rise in temperature ration of aluminium and iron is $\frac{\Delta T_{Al}}{\Delta T_{Fe}}=\frac{m_{iron}{s}_{iron}}{m_{aluminium}{s}_{aluminium}}=\frac{1}{4}$

Thus the rise in temperature of the iron block is four times the increase in temperature of the aluminum block