An aluminium measuring tape which is correct at 100-C measures the length of a line as 80 cm at 50- If thermal coefficient of linear expansion of aluminium is of 2-50 - 10-5 per-C the correct length of the line is

The correct option is C 80.08cm L'=L_0(1+ α_0 δ(T)) 80=L_0(1+ #160;(2.5× 10^ 5)( 50)) 80= L_0 (0.99875) L_0 = 80.1 cm ...

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Standard XII

Physics

Thermal Expansion

An aluminium ...

Question

An aluminium measuring tape which is correct at $100^{\circ} C$ measures the length of a line as 80 cm at $50^{\circ}$ . If thermal coefficient of linear expansion of aluminium is of $2.50 \times 10^{- 5} p e r^{\circ} C$ the correct length of the line is

79.92 cm

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79.68 cm

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80.08cm

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80.32 cm

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Solution

The correct option is C 80.08cm
$L^{'} = L_{0} (1 + α_{0} δ (T))$
$80 = L_{0} (1 + (2.5 \times 10^{- 5}) (- 50))$
80= $L_{0}$ (0.99875)
$L_{0}$ = 80.1 cm

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An aluminium measuring tape which is correct at 100∘C measures the length of a line as 80 cm at 50∘. If thermal coefficient of linear expansion of aluminium is of 2.50×10−5 per∘C the correct length of the line is

The correct option is C 80.08cmL′=L0(1+α0δ(T))80=L0(1+(2.5×10−5)(−50))80=L0(0.99875)L0= 80.1 cm

An aluminium measuring tape which is correct at $100^{\circ} C$ measures the length of a line as 80 cm at $50^{\circ}$ . If thermal coefficient of linear expansion of aluminium is of $2.50 \times 10^{- 5} p e r^{\circ} C$ the correct length of the line is

The correct option is C 80.08cm
$L^{'} = L_{0} (1 + α_{0} δ (T))$
$80 = L_{0} (1 + (2.5 \times 10^{- 5}) (- 50))$
80= $L_{0}$ (0.99875)
$L_{0}$ = 80.1 cm