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An aluminium rod of 10 m length at 20oC expand when the temperature is changed from 0oC to 100oC. The resultant change due to rod expansion (in mm) is
[thermal expansion coefficient (γ) of at 20oC is 25×106(1/oC)]
  1. 25

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Solution

The correct option is A 25
If we have a rod of length lo at temperature To & the temperature is raised to a new value T, the rod will be found to have a new value l. Then the relation is
l=lo[l+γΔT]

Where ΔT=TT0

γ= linear thermal expansion coefficient

At 0oC

l1=10×[1+25×106(020)]

=9.995 m

At 100oC

l2=10×[1+2.5×105](10020)]

=10.02 m

The rod expansion is

l2l1=25 mm

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