Question

An aluminum measuring rod which is correct at $5^{\circ }C$, measure a certain distance as 88.42 cm at ${35}^{\circ }C$. Determine the error in measuring the distance due to the expansion of the rod.

$\alpha =24\times {10}^{-6}{C}^{-1}$

• A. $0.014cm$
• B. $0.054cm$
• C. $0.064cm$
• D. $0.044cm$

Answer 1

The correct option is C $0.064cm$

The error in measuring distance will be equal to the length expansion corresponding to the measured length. Hence,

$e=\Delta l=88.42\left({\alpha }_{Al}\right)\Delta T$

$e=88.42(24\times {10}^{-6})(35-5)cm\approx 0.064cm$

Answer is $0.064cm$