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Byju's Answer
Standard XII
Physics
Principle of Superposition
An Am signal ...
Question
An Am signal is modulated by 50% such that FOM of AM. becomes equal to the Figure of ment (FOM) of FM signal is FM modulated. The modulation index of FM will be _________
0.272
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Solution
The correct option is
A
0.272
0.272 (0.25 - 0.30)
(
F
O
M
)
A
M
=
η
=
μ
2
2
+
μ
2
(
F
O
M
)
F
M
=
3
2
β
2
μ
2
2
+
μ
2
=
3
2
β
2
β
2
=
2
3
[
1
/
4
2
+
1
/
4
]
=
2
3
[
1
9
]
=
2
27
=
0.074
β
=
√
0.074
=
0.272
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