Question

An AM wave is expressed as $e=10(1+0.6\cos 2000\pi t)\cos 2\times {10}^8\pi t$ volts, the maximum and minimum value of modulated carrier wave are

• A. $10V$ and $20V$
• B. $4V$ and $8V$
• C. $16V$ and $4V$
• D. $8V$ and $20V$

Answer 1

Answer: (C)

$16V$ and $4V$

$E_{max}=(1+m_a)E_c=(1+0.6)\times 10=16V$.
$E_{min}=(1-m_a)E_c=(1-0.6)\times 10=4V$.