Question

An AM wave varies from $10V$ to $4V$. Its percent modulation is

• A. $36\%$
• B. $42.8\%$
• C. $54\%$
• D. $68\%$

Answer 1

The correct option is B $42.8\%$

$=E_{max}=10,E_{min}=4$

$m_a=\frac{E_{max}-E_{min}}{E_{max}+E_{min}}=\frac{10-4}{10+4}=\frac{6}{14}=.428$

$\Rightarrow m_a=42.8\%$