CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

An ammeter and a copper voltameter are connected in series through which a constant current flows. The ammeter shows 0.52 ampere. If 0.635 g of copper is deposited in one hour, what is the percentage error of the ammeter?
(At. mass of copper =63.5)

Open in App
Solution

The electrode reaction is:
Cu2+1 mole+2e2×96500 CCu
63.5 g of copper deposited by passing charge
=2×96500 coulomb
0.635 g of copper deposited by passing charge
=2×9650063.5×0.653 coulomb
=2×965 coulomb
=1930 coulomb
We know that,
Q=I×t
1930=I×60×60
I=19303600=0.536 ampere
Percentage error =(0.5360.52)0.536×100=2.985.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Faraday's Laws
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon