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Question

An ammeter, suspected to give inaccurate reading, is connected in series with a silver voltameter. The ammeter indicates. 0.54 A. A steady current passed for one hour deposits 2.0124 gm of silver. If the e.c.e. of silver is 1.118×103 gmC1, then the error in ammeter reading is

A
+0.04 A
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B
+ 0.02 A
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C
-0.03 A
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D
- 0.01 A
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Solution

The correct option is B +0.04 A
Use the formula,m=ZIt

I=mZt

Actual current=I=2.01241.118×103160×60=0.50A

Error=0.540.50=+0.04 A

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