Question

An amorphous solid (X) burns in air to form a gas (Y) which turns lime water milky. This gas decolourises aqueous solution of acidified $KMn{O}_4$. Gas (Y) reacts with oxygen to give another gas (Z) which is responsible for acid rain. X, Y, and Z are:

• A. $C\left(X\right),CO\left(Y\right),C{O}_2\left(Z\right)$
• B. $S\left(X\right),S{O}_2\left(Y\right),S{O}_3\left(Z\right)$
• C. $P\left(X\right),P_2{O}_3\left(Y\right),P_2{O}_5\left(Z\right)$
• D. $S\left(X\right),S{O}_3\left(Y\right),C{O}_2\left(Z\right)$

Answer 1

Answer: (B)

$S\left(X\right),S{O}_2\left(Y\right),S{O}_3\left(Z\right)$

Hence as shown in above image: X=$S$ , Y=$S{O}_2$ , Z=$S{O}_3$

Therefore, option B is correct.