An amount of $100 j o u l e s$ of work is done in moving a charge of $5 c o u l o m b s$ from one terminal of the battery to another. What is the potential difference of the battery?

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Solution

Step 1- Given data
Charge, $Q = 5 C$
Work done, $W = 100 J$
Step 2- Formula used
The formula for the potential difference $∆ V$ is
$∆ V = \frac{W}{Q}$
Step 3- Finding the potential difference of the battery
$∆ V = \frac{W}{Q} ∆ V = \frac{100 J}{5 C} ∆ V = 20 V$
Final answer- The potential difference of the battery is $20 V$ .

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An amount of 100joules of work is done in moving a charge of 5coulombs from one terminal of the battery to another. What is the potential difference of the battery?

Step 1- Given dataCharge, Q=5CWork done, W=100JStep 2- Formula usedThe formula for the potential difference ∆V is ∆V=WQStep 3- Finding the potential difference of the battery∆V=WQ∆V=100J5C∆V=20VFinal answer- The potential difference of the battery is 20V.

An amount of $100 j o u l e s$ of work is done in moving a charge of $5 c o u l o m b s$ from one terminal of the battery to another. What is the potential difference of the battery?