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An amount of $100 k W$ of heat is transferred through a wall in steady state. One side off the wall is maintained at $127^{o} C$ and the other side at $27^{o} C$ The entropy generated (in $W / K$ ) due to the heal transfer through the wall is

83.33

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Solution

The correct option is A 83.33
As it is given that process is steady so heat trnasfer through the wall will be:

$S_{2} - S_{1} = \int_{1}^{2} \frac{d Q}{T} + S_{g e n} = \frac{Q}{T_{1}} - \frac{Q}{T_{2}} + S_{g e n}$
$∴ 0 = \frac{100}{400} - \frac{100}{300} + S_{g e n}$
or $S_{g e n} = \frac{1}{3} - \frac{1}{4} = \frac{1}{12} k W / K$
$∴ S_{g e n} = \frac{1000}{12} W / K = 83.33 W / K$

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