Question

An amount of 250 joules of work done in transferring 20 coulombs of charge from one terminal of a battery to another. What is the potential difference between the two terminals of the battery?

Answer 1

Concept used: Potential difference

Prerequisite: Knowledge of the potential difference

Step 1: Given data,

1. The amount of work done is W=250 J.
2. The charge to be moved is q=20 C.

Step 2: Calculate the potential difference,

The expression for the potential difference between the two terminals of the battery is given by,

$∆V=\frac{W}{q}$

Here, $∆V$ is the potential difference.

Substitute the given values in the above equation,

$$\begin{gathered} V=\frac{250\text{J}}{20\mathrm{C}} \\ V=12.5\text{volts} \end{gathered}$$

Thus, the potential difference between the two terminals of the battery is 12.5 V.