An analytic function of a complex variabel z=x+iy is expressed as f(x)=u(x,y)+iv(x,y) where i=√−1. If u=xy, the expression for v should be
A
(x+y)22+k
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B
x2−y22+k
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C
y2−x22+k
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D
(x−y)22+k
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Solution
The correct option is Cy2−x22+k Given function is f(z)=u(x,y)+iv(x,y) u(x,y)=xy
By Cauchy - Riemann equations ∂v∂y=∂u∂x=y ⇒v=y22+f(x) ... (i)
Again, ∂u∂y=−∂v∂x ⇒x=−f′(x) ⇒f(x)=−x22+k
So by (i), v=y2−x22+k