Question

An angle ${10}^0$ more than three times its complementary angle. Then find the angles.

Answer 1

Let one angle be $x$, then larger angle is $3x+{10}^{\circ }$.

We know, two angles are said to be complementary, if the sum of their measures is ${90}^{\circ }.$

$⟹$ $x+3x+{10}^{\circ }={90}^{\circ }$

$⟹$ $4x={80}^{\circ }$

$⟹$ $x={20}^{\circ }.$

Hence, the smaller angle is $x={20}^{\circ }$

and larger angle is $3x+{10}^o=3\left({20}^o\right)+{10}^o={60}^o+{10}^o={70}^{\circ }.$