Question

An angle is ${14}^o$ more than its complementary angle. What is the measure?

Answer 1

Let the first angle is $=x^o$

Then, the second angle is $=x+{14}^o$.

We know that, if two angles are complementary, then their sum is ${90}^o$.

According to given question,

$x+x+14={90}^o$

$⟹$ $2x={90}^o-{14}^o$

$⟹$ $2x={76}^o$

$⟹$ $x={38}^o$.

Hence, the angles are $x={38}^o$

and $x+{14}^o={38}^o+{14}^o={52}^o$.